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ankit

· started a discussion

· 1 Months ago

Ankit (Question: 246971.0 )

sir a and b are integers with your value ie a=26 b cant be an integer..a must be 28 to satisfy above all equations...kindly review your solution

Question:
If the arithmetic mean of 6a and 8b is greater than 100 and a is four times of b, then the smallest possible integer value of a is –
Options:
A) 28
B) 26
C) 32
D) 24
Solution:

Ans: (b)


Sumit Sharma

· commented

· 1 Months ago

sai h bhai answer,,b k liye koi condition ni h..

pankaj deb

· commented

· 1 Months ago

no where it is said that b is integer

Amit

· commented

· 1 Months ago

When b is 6.5 then a is 26 bcz this is d least value of b which makes it greater than 100

Harsh Ahlawat

· commented

· 1 Months ago

its nowhere written that b is an integer
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