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Pranay SB

· started a discussion

· 1 Months ago

Alternate solution: (Question: 271926.0 )

A(+)=20 mins
B(-) =60 mins
Total work: (LCM of 20 &60)=60
20 3 (+)
60
60 1 (-)
-----
2 (1 min work)
Half is filled, so, 30 units of work is done;
A & B completes 30 units of work in (30/2)=15 mins;
Then A(+) is turned off and only B(-) runs;
Remaining work (30 units) will be completed by B in (30/1)=30 mins;
Total time=15mins+30mins=45 mins; and so, 5:45 PM

Question:

Tap A fills a tank in 20 min while B empties it at  13   rd the rate at which A fills it. At 5 pm, A and B are simultaneously started and the tank is 50% full, tap A is turned off. At what time will the tank be empty?

Options:
A)

12 : 00 AM

B)

5 : 30 PM

C)

5 : 45 PM

D)

6 : 00 PM

Solution:

Ans: (c)

  

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
Yes, you can solve by this method also.

Team TR

Pranay SB

· commented

· 1 Months ago

The lines alignment is missing. So, you would find ambiguity. Sorry. (3-1)=2; and ignore middle '60'

Pranay SB

· commented

· 1 Months ago

20 3(+)
60 1(-)
------------
2
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