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Munagala Janardhana Reddy

· started a discussion

· 1 Months ago

let for s1,c1 selling and cost prices loss=20% ==>(s1/c1)=(80/100) --->eq1
s1 per each lemon = 40/45
let for s2,c2 selling and cost prices profit=20%==>(s2/c2)=(120/100) ->eq2
s2 per each lemon =24/n
(eq1/eq2)=(80/120)=2/3=[(40/45)/(24/n)]
thus No of lemons at s2 is ::n=18::

Question:

By selling 45 lemons for Rs.40, a man loses 20%. How many should he sell for Rs.24 to gain 20% in the transaction?

Options:
A)

16

B)

18

C)

20

D)

22

Solution:

Ans: (b)

  

Munagala Janardhana Reddy

· commented

· 1 Months ago

c1=c2

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