CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
Munagala Janardhana Reddy

· started a discussion

· 1 Months ago

alternate solution (Question: 108026.0 )

R=circumradius=OP=PD=PC=1 unit
and OA=OB=1 unit
then CD=2 units
let OD=OC=x
(OD^2 +OC^2)=4=CD^2
Then OC=OD=root(2)
AC=OC-OA =root(2) - 1
then AC+CP=root(2)=1.414

Question:
In the given figure, the radius of the circle is 1 mtr. If AC = BD and CD is a tangent at point P, then the value of AC + CP will be:


Options:
A) 105 cm
B) 141.4 cm
C) 138.6 cm
D) 282.8 cm
Solution:
Ans: (b)

Given :

OA = OB = radius = 1 metre

\(\because\)AC = BD (Given)

\(\therefore \) OC = OD

Thus, the triangle COD is a right angled isosceles triangle.

\(\therefore\)\(\angle \)OCD = \(\angle \)ODC = 45°

In \(\triangle\)OCP,

\(\angle \)COP = 45° \(\Rightarrow\) OP = CP = 1

\(\therefore\) OC = OA + AC

\(\sqrt{2}=1+AC\Rightarrow AC=\sqrt{2}-1\)

A.T.Q.,

AC + CP = \(\sqrt{2}-1+1=\sqrt{2}= 141.4\) cm

jyoti dahiya

· commented

· 1 Months ago

it is not given that p is mid point then how u consider it mid point

Varun

· commented

· 1 Months ago

OP will not be circumradius because P is not surely a mid point of CD as it is not given in the Q

Swati Suman

· commented

· 1 Months ago

nice explained

Sumanth

· commented

· 1 Months ago

Super bro
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions