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Sumit Sharma

· started a discussion

· 1 Months ago

alternate (Question: 246326.0 )

we can also use mixture allegation here

male female

75% x%

55

3 2

x=25%=1/4(earn more than 35000)
so answer is 1-(1/4)=3/4(earn less than or equal to 35000)

Question:
40% of the employees of Reliance industries are female, and 75% of the men earn more than Rs.35000 per year. If 55% of the company employees earn more than Rs.35000 per year, what fraction of the women employed by the company earn Rs.35000 per year or less ?
Options:
A) \(\cfrac{1}{4}\)
B) \(\cfrac{3}{4}\)
C) \(\cfrac{3}{7}\)
D) \(\cfrac{2}{7}\)
Solution:

Ans: (b)

Let the total employee = 100

So, Female = 40  Male = 60


Knowledge Expert

· commented

· 1 Months ago

Dear Student,
You can solve using this method also.
There are several ways to solve a problem.

Thanks and Regards
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