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Gurdeep Kaur

· started a discussion

· 1 Months ago

abstrusely solved (Question: 259920.0 )

can somebody please explain how it has been done? solution is not easy to get.

Question:

Gagandeep and Hemant are two persons, but when they worked together, they complete in 20 days. Had Gagandeep worked at half of his efficiency and Hemant at 6 times of his efficiency, it would have taken them to finish the job in 33 13   % of the scheduled time. In how many days Gagandeep can complete the job working alone?

Options:
A)

33 13    days

B)

33 23   days

C)

36 23    days

D)

40 days

Solution:

Ans: (c)

  

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Given answer is correct
According to Question
Let the eff. 0f gagandeep = x
and the eff. of hemant = Y
x + Y = (x/2 + 6Y) 1/3
3x + 3y = x/2 + 6y
3x - x/2 = 6y - 3y
5x = 6y
x = 6 , y = 5
total work = 11 x 20 = 220
Req. time for gagandeep = 220/6

Best wishes
Team TR

ankur

· commented

· 1 Months ago

you simply solve LHS =RHS ,you will get X:Y =6:5,these kind of improper solutions just bamboozle the students
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