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Pradeep Kumar

· started a discussion

· 1 Months ago

A Simpler approach (Question: 107807.0 )

Profit on giving 880g instead of 1000g:

(120/880)*1/100= 150/11% profit (say p1)

second profit is k% (say p2)

p1+p2+(p1*p2)/100=25(given)

We can get k=25 %

Question:

A trader sells goods to his customer at a profit of K% over the cost price, besides it he cheats his customer by giving 880 gm instead of 1 kg. Thus, his overall profit percent is 25%. Find the value of K.

Options:
A) 8.33%
B) 8.25% 
C) 10% 
D) 12.5%
Solution:
Ans: (c) 



Alternate:


Let C.P. of 1000g = Rs. 1000
Profit % = K %
Profit = K/100 x 1000 = Rs.10 K
He then cheats his customer by giving 880g only instead of 1kg,
So, C.P of 880g = Rs. 880
S.P. of 880g = 1000 + 10K
Profit % = [ ( 1000 + 10K - 880 ) / 880 ] x 100 = 25
K = 10%

Pradeep Kumar

· commented

· 1 Months ago

last line, we can get k=10 % (typo)
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