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ramesh bairwa

· started a discussion

· 1 Months ago

a (Question: 222759.0 )

solution?

Question:
The value of the expression \(\left ( \cfrac {1}{2^2 - 1} \right )\) + \(\left ( \cfrac {1}{4^2 - 1} \right ) + \left ( \cfrac {1}{6^2 - 1} \right ) \) + ...........+ \(\left ( \cfrac {1}{20^2 - 1} \right )\) is equal to -
Options:
A) \(\cfrac{9}{19}\)
B) \(\cfrac{10}{19}\)
C) \(\cfrac{10}{21}\)
D) \(\cfrac{11}{21}\)
Solution:
Ans: (c)


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