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ramesh bairwa

· started a discussion

· 1 Months ago

a (Question: 220235.0 )

solution?

Question:
Maximum value of (8sin\(\theta\) + 3cos\(\theta\)) is –
Options:
A) \(\sqrt{63}\)
B) \(\sqrt{56}\)
C) \(\sqrt{73}\)
D) \(\sqrt{11}\)
Solution:
Ans: (c) Maximum value of a sin\(\theta\) + b cos \(\theta\)

= \(\sqrt{a^2 + b^2}\)

\(\therefore\) Maximum value of 8 sin\(\theta\) + 3 cos\(\theta\)

= \(\sqrt{64 + 9}\)  = \(\sqrt{73}\)

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