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sawan kumar
· commented
· 1 Months ago
Knowledge Expert
· commented
· 1 Months ago
2 is the required answer.
Its common to all that the remainder of any number when divided by 10 is it's unit digit.
Therefore, finding the remainder of 2^33 when divided by 10 is equivalent of finding the unit digit of 2^33.
Let U(x ) be a function which gives out the unit digit of x.
Now, we observe
U(2^1)=2
U(2^2)=4
U(2^3)=8
U(2^4)=6
U(2^5)=2
……………
Therefore this pattern continues.
Every 4th power ends with 6 and the next one 2.
33=4×8+1
Hence , the number ends with 2.
Consequently, the remainder and the required answer is 2.
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