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ramesh bairwa

· started a discussion

· 1 Months ago

a (Question: 196721.0 )

solution?

Question:
In the given figures, PT is the tangent of a circle with centre O at point R. If diameter SQ is increased, it meets with PT at point P. If \(\angle \)SPR = x° and QSR = y°, what is the value of x° + 2y° ?


Options:
A) 90°
B) 105°
C) 135°
D) 180°
Solution:
Ans: (a)


pradeep kumar

· commented

· 1 Months ago

Yet to be approved!

Pooja yadav

· commented

· 1 Months ago

Yet to be approved!
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