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ankit

· started a discussion

· 1 Months ago

67 (Question:636391.0)

question number

Question:
The length and breadth of the floor of a room are 20 feet and 10 feet respectively. Square tiles of side 2 feet of three different colors are to be laid on the floor. White tiles are laid in the first row and all sides. If black tiles are laid in one third of the remaining and green tiles in the rest, how many green tiles will be there ?
Options:
A) 16
B) 48
C) 24
D) 32
Solution:

Ans (a)

Area left after laying black tiles = [(20 - 4)\(\times\) (10 - 4)] sq ft = 96 sq. ft.

Area under white tiles = \(( \frac{1}{3}\times 96 )\) sq. ft = 32 sq. ft.

Area under green tiles = (96 - 32) sq. ft .= 64, sq. ft.

Number of green tiles =\(\big( \frac{64}{2\times2} \big)\) = 16.


Knowledge Expert

· commented

· 1 Months ago

Dear student
Area of the floor = 20 × 10 = 200 sq.ft
Area covered by black tiles
= 2 (20 + 20 + 6 + 6)
=104 sq.ft.
Remaining space
= 200 - 104 = 96 sq.ft.
Area covered by white tiles
= 1/3 × 96 = 32 sq.feet
Area covered by blue tiles
= 96 - 32 = 64 sq.feet
Area of 1 tile = (2)^2 = 4 sq.ft
No. of blue tiles = 64/4 = 16

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