6 (Question: 277481.0 )

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Mishthi Pandey

· started a discussion

· 1 Months ago

6 (Question: 277481.0 )

ans shuld be c

Question:

ABC is triangle is which AB = AC and P is a point on side AC. A line is drawn from point C in such a way that it intersects which produced BP at Q and $∠$ ABQ = $∠$ ACQ what is $∠$ AQC?

Options:

$90^{o} - \frac{1}{2} ∠ B A C$

$90^{o} + \frac{1}{2} ∠ A C B$

$90^{o} - \frac{1}{2} ∠ A B C$

$90^{o} + \frac{1}{2} ∠ B A C$

Solution:

Ans: (d)

Vaibhav Yadav

· commented

· 1 Months ago

No d is correct
AQC = 180- ABC (cyclic or apply same angles theorem)
AQC = BAC+ACB ( same segment)
add both equation
2 AQC = 180 - BAC ( ABC=ACB )
AQC =90+1/2 BAC

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6 (Question: 277481.0 )

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