CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
Keshab singh

· started a discussion

· 1 Months ago

22 (Question: 456102.0 )

cant understand the soln clearly

Question:
ABCD is a square and each side is of 4cm. A point P is on AD; find the minimum possible length of BP and CP together (in cm).
Options:
A) 4\(\sqrt[]{5}\)
B) \(5\sqrt[]{5}\)
C) \(6\sqrt[]{3}\)
D) \(4\sqrt[]{4}\)
Solution:


For minimum value of BP and CP, 

x=y

It is possible only when AP = PD=2 

∴ x=y =\(\sqrt[]{4^2+2^2}\)  = 2√5

∴ (BP+CP)min=2√5 +2√5=4√5

Knowledge Expert

· commented

· 1 Months ago

Dear student
APB and CPD are right angled triangle,
so by using Pythagoras theorem we will
find out PB and PC.

Keep learning
Team TR
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions