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chandrasekhar

· started a discussion

· 1 Months ago

20 (Question:108149.0)

Video plz

Question:

If sinθ + sin2θ = 1, then the value of cos12θ + 3 cos10θ + 3 cos8θ + cos6θ – 1 is:

Options:
A) 0
B) 1
C) 2
D) 3
Solution:
Ans: (a)

sin\(\theta\) + sin2\(\theta\) = 1 \(\Rightarrow\) sin\(\theta\) = cos2\(\theta\)

Given : cos12\(\theta\) + 3 cos10\(\theta\) + 3 cos8\(\theta\) + cos6\(\theta\)–1

= (cos4\(\theta\) + cos2\(\theta\))3 – 1 = (sin2\(\theta\) + cos2\(\theta\))3 – 1 = 1 – 1 = 0

Knowledge Expert

· commented

· 1 Months ago

Dear student, Currently it is not available but we will look towards your issue. thanks for showing your interest. Keep learning, Team TR
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