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chandan kumar

· started a discussion

· 1 Months ago

189624 (Question: 189624.0 )

cos2x =1-tan^2/1+tan^2

Question:
If \(\cfrac{tan\ 26^o+tan\ 19^o}{x(1-tan\ 26^o.\ tan\ 19^o)}\), then the value of x is –
Options:
A) 1
B) \(\sqrt[]{2}\)
C) 2
D) \(\sqrt[]{3}\)
Solution:

Knowledge Expert

· commented

· 1 Months ago

Hi Chandan, your formula is correct, what's you doubt?
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