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Rohan Satija

· started a discussion

· 1 Months ago

1.1C.P-C.P=1.1C.P-132-(CP-10)
0.1C.P=1.1C.P-132-0.9C.P
0.1C.P=0.2C.P-132
132=0.1CP
1320=C.P

Question:

A dealer sells a radio at a gain of 10%. If he had bought it at 10% less and sold it for Rs. 132 less, he would have still gained 10%. The cost price of radio is – 

Options:
A) Rs. 1,100
B) Rs. 1,200
C) Rs. 1,300
D) Rs. 1,320
Solution:
Ans: (b) Let Cost price = Rs. 100 


If Rs. 11 is less than C.P. of radio = Rs. 100 

If Rs. 132 is less than C.P. of radio 

= Rs. \(\left (100 × \cfrac {132}{11} \right )\)

= Rs. 1200

Rohan Satija

· commented

· 1 Months ago

Correction in first line LHS=1.1C.P-132-(C.P-0.1CP)

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