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Himanshu Singh

· started a discussion

· 1 Months ago

107798.0 (Question: 107798.0 )

qus is good but the solution is incorrect bcz QC is not the longest median btw ... the other median passing from A would b the longest median hence the largest side of the needed triangle .

Question:

The semi-perimeter of a right angled triangle ABC is 12 cm and the shortest median is 5 cm. What is area of the triangle which has the largest median of triangle ABC as its longest side?

Options:
A) \(\sqrt[]{73}\) cm2  
B) 10 cm2
C) 12 cm2  
D) None of these
Solution:
Ans: (c) 


Given: S = 12 cm & BP = 5 cm

∴ AP = PC = BP = 5 cm

∴ AC = 10 cm

 We know the ratio of Right triangle like (3:4:5) 

      then we assume the ratio, (6:8:10)

So, the other two sides = 8 cm, 6 cm

∴ Area of ∆QBC = \(\cfrac{1}{2}\times\) QB × BC = \(\cfrac{1}{2}\times\) 4 × 6 = 12 cm2

Knowledge Expert

· commented

· 1 Months ago

Dear student Solution is correct. Please try again Best wishes Team TR

Pramod Kumar Verma

· commented

· 1 Months ago

yes longest median will be on BC from point A

arunesh

· commented

· 1 Months ago

yes, longest median would be AR. However Answer would be same as 1/2*AB*BR=1/2*8*3=12
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