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· 1 Months ago

plz explain

Question:
If \(\cfrac{x^2}{by +cz}\) = \(\cfrac{y^2}{cz + ax}\) = \(\cfrac{z^2}{ax + by}\) = 2, then  \(\cfrac{c}{2c + z}\)  + \(\cfrac{b}{2b + y}\)  + \(\cfrac{a}{2a + x}\)equals to –
Options:
A) 3
B) 2
C) 4
D) \(\cfrac{1}{2}\)
Solution:
Ans: (d)


= \(\cfrac{1}{2}\)  \(\left [ \cfrac {cz}{ax + by + cz} \ + \cfrac{by}{ax + by + cz} + \cfrac{ax}{ax + by + cz} \ \ \right ]\) 

= \(\cfrac{1}{2}\) = \(\left [ \cfrac {ax + by + cz}{ax + by + cz} \ \ \ \ \right ]\) = \(\cfrac{1}{2}\)

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