CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Tags:

Articles

Discussions
Submit Discussion
SAHIL

· started a discussion

· 1 Months ago

Wrong Wrong Wrong Answer (Question: 110892.0 )

it should be >=

Question:
DIRECTION : In the given question two equations numbered I and II are given. You have to solve both the equations and Give answer if


I. 225x2 – 4 = 0

II. \(\sqrt{225y}\)  + 2 = 0

Options:
A) x > y
B) x ≥ y
C) x < y
D) x ≤ y
E) x = y or the relationship cannot be established
Solution:

I. 225x2 – 4 = 0

225x2 = 4

x2 = \(\frac{4}{225}\) 

x = \(\sqrt{\frac{4}{225}}\)  = ± \(\frac{2}{15}\) 

II. \(\sqrt{225y}\)  + 2 = 0

 \(\sqrt{225y}\) = -2

Squaring both sides we get, 

225y = 4

y = \(\frac{4}{225}\)  

Knowledge Expert

· commented

· 1 Months ago

x=+2/15 and -2/15 and y=4/225

x=+0.1333 and -0.1333 and y=0.1777

compare now,

0.1333<0.1777 means x<y
-0.1333<0.1777 means x<y

so, on combining, we get x<y

Thats it..
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions