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Priyanshi Sharma

· started a discussion

· 1 Months ago

Wrong solution (Question:229010.4)

The answer and solution is wrong

Question:

DIRECTIONS: Study the following pie chart and table carefully and answer the questions that follow.

Time (hours/minutes) taken by the pipes to fill a tank/cistern

Two pipes E and F are opened simultaneously and it is found that due to leakage in the bottom of the tank it took 48 minutes excess time to fill the cistern. When is the cistern full, in what time will the leak empty it?

Options:
A)

72 hours

B)

62 hours

C)

64 hours

D)

84 hours

E)

None of these

Solution:

Ans: (a) Work done by the two pipes in 1 hour = (1/12) + (1/18) = (15/108).

Time taken by these pipes to fill the tank = (108/15)hrs = 7 hours 12 min.

Due to leakage, time taken = 7 hours 12 min + 48 min = 8 hours

Work done by two pipes and leak in 1 hour = 1/8.

Work done by the leak in 1 hour = (15/108)-(1/8) = (1/72).

Leak will empty the full cistern in 72 hours.

Knowledge Expert

· commented

· 1 Months ago

Dear student,
The question and the solution is correct...
If there are no leakage then time taken by both pipe to fill the tank=60/7 if there will be leakage then total time to fill the tank=60/7+17/7=77/7=11 minutes so 1 minute work=1/11 part Thank You
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