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sivabala

· started a discussion

· 1 Months ago

wrong solution (Question: 100166.0 )

X=-3 = y= -3 then x= 4 > y= -2,,,,so answer X is greater than or equal to Y

Question:
DIRECTIONS: In the given question two equations numbered I and II are given. You have to solve both the equations and give answer if:

I. x2 – x – 12 = 0


II. y2 + 5y + 6 = 0 

Options:
A) x > y
B) x ≥ y
C) x < y
D) x ≤ y
E) x = y or the relationship cannot be established
Solution:

I. x2 – x – 12 = 0

⇒ x2 – 4x + 3x – 12 = 0

⇒ x (x – 4)+ 3(x – 4) = 0

⇒ (x – 4) (x + 3) = 0

∴ x = 4 or – 3

II. y2 + 5y + 6 = 0

⇒ y2 + 3y + 2y + 6 = 0

⇒ y (y+3) + 2 (y+3) = 0

⇒ (y + 3) (y+2) =0

∴ y = – 3 or – 2 

kanhaiya jha

· commented

· 1 Months ago

Its ok, You must try our IBPS PO Mock Test Seires: https://www.toprankers.com/bank-exams/ibps-po-package/online-tests

sivabala

· commented

· 1 Months ago

ok ok sorry sorry

kanhaiya jha

· commented

· 1 Months ago

From I, x = 4 or – 3
From II, y = – 3 or – 2

Now, correlate x and y,
4>-3 means x>y
4>-2 means x>y
-3=-3 means x=y
-3<-2 means x<y

So, all the three signs appear. Hence No relationship can be established.
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