CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Tags:

Articles

Discussions
Submit Discussion
Nitesh Agarwal

· started a discussion

· 1 Months ago

wrong question (Question: 122185.0 )

the question is wrong, here ball should be there instead of cap. if cap is there then the ans should be 1/55. Bcoz in the question itself it is already mentioned that 2 balls are drawn. So considering the correct question the ans is 2c2/11c2. which is 1/55

Question:
A box contains 2 blue balls, 4 red balls, 5 green balls and 1 yellow ball. If two balls are picked randomly, what is the probability that both are blue?
Options:
A) \(\cfrac{1}{55}\)
B) \(\cfrac{1}{22}\)
C) \(\cfrac{1}{33}\)
D) \(\cfrac{1}{66}\)
E) \(\cfrac{1}{6}\)
Solution:
Required probability =  \(\cfrac{^2C_2}{12C_2}=\cfrac{1}{66}\)  

Knowledge Expert

· commented

· 1 Months ago

Given answer 1/66 is correct...

Q is: A box contains 2 blue balls, 4 red balls, 5 green balls and 1 yellow ball. If two balls are picked randomly, what is the probability that both are blue?

Akshay

· commented

· 1 Months ago

Good one Sir
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions