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arindam ghosh

· started a discussion

· 1 Months ago

angle pab (not = to) angle pcb

Question:

O is the center of circle and ∠PAB = 40°, then ∠PCA =? 


Options:
A) 60°                               
B) 50°  
C)  45° 
D) 65° 
E) 75° 
Solution:

Ans:(b)


Join PB  and PC

∠PAB = ∠PCB = 40°

are the angle of same sector

angle on Circumference formed by the diameter of circle/∠ACB = 90° 

then, ∠PCA + ∠PCB = ∠ACB

∴ ∠PCA= 90° - 40° = 50° 

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