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swati

· started a discussion

· 1 Months ago

wrong (Question: 104273.0 )

between 1/2 and 3/4 , 3/4 is greater so here one is coming so ans will be CND

Question:
DIRECTIONS: In each question two equations numbered I and II are given. You have to solve both the equations and Give Answer If


I. 6x2 – 7x + 2 = 0

II. 20y2 – 31y + 12 = 0

Options:
A) x < y
B) x > y
C) x ≥ y
D) x ≤ y
E) x = y or relationship between x and y cannot be established.
Solution:

I. 6x2 – 7x + 2 = 0

⇒ 6x2 – 4x- 3x + 2 = 0

⇒ 2x(3x - 2) -1 (3x - 2) = 0

⇒ (2x - 1) (3x - 2) = 0

⇒ x =  \(\frac{1}{2}\) or \(\frac{2}{3}\) 

II. 20y2 – 31y + 12 = 0

⇒ 20y2 - 15y - 16y + 12 = 0

⇒ 5y(4y - 3) - 4 (4y - 3) = 0

⇒ (4y - 3) (5y - 4) = 0

⇒ y = \(\frac{3}{4}\)  or  \(\frac{4}{5}\) 

ARCHANA SONONE

· commented

· 1 Months ago

ans is correct....1/2=0.5 2/3=0.6 3/4=0.7 4/5=0.8
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