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ravi jadaun

· started a discussion

· 1 Months ago

wrong (Question:1010420.3)

some problem in this answer plz check it again

Question:

DIRECTIONS: 

Two equations numbered I and II are given. You have to solve both the questions and given answer.

I.  2x2    â€“ 6\(\surd\)3x + 12 = 0

II.  2y2    â€“3\(\surd\) 2y + 2 = 0

Options:
A)

If x  ≥    y

B)

If x  ≤    y

C)

If x > y

D)

If x < y

E)

If x = y or the relationship between x and y can't be established.

Solution:

    

Ans: (c)

  

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
Answer solution and marked answer is correct.

Regards
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