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arfat

· started a discussion

· 1 Months ago

wrong answer (Question:164921.2)

wrong answer

Question:
DIRECTIONS: In the following questions, two equations numbered I and II are given. Solve both the equations and given your answer as

I. 4P2 + 7P - 2 = 0 

II. 3q2 + 2q - 1 = 0
Options:
A)

If p > q 

B) If p ≥ q
C) If p < q
D) If p ≤ q
E) If p = q or relationship cannot be established
Solution:
Ans: (e) 

I.

4P2 + 7P - 2 = 0 

4P2 + 8P – P - 2 = 0

4P(P +2) – (P + 2) = 0

(4P - 1)(P + 2) = 0

If 4P - 1 = 0 then P = 1/4

If P + 2 = 0 then P = -2

II.

3q2 + 2q - 1 = 0

3q2 + 3q – q - 1 = 0

3q(q + 1) – (q + 1) = 0

(3q - 1)(q + 1) = 0

If 3q - 1 = 0 then q = 1/3

If q + 1  = 0 then q = -1

As, p = 1/4, p = -2 and q=1/3, q=-1

Hence, relation cannot be established 

Knowledge Expert

· commented

· 1 Months ago

Dear Student, Correlate the values of p and q properly. As we have, p = -2, 0.25 and q = 0.33, -1 -2<0.33 means p<q -2<-1 means p<q 0.25<0.33 means p<q 0.25>-1 means p>q < and > never occur together, so no relationship can be made. Keep Learning with Us Best Wishes Team Toprankers
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