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kundan

· started a discussion

· 1 Months ago

min perc gth in 2007-2008--25%

Question:
DIRECTIONS: The figure below represents the total number of students and the number of girls in college ABC for the five years from 2005-06 to 2009-10. During this period, the total number of students increased from 100 to 700, while the number of girls increased from 50 to 400.


The minimum percentage growth in the total number of girls, relative to the previous year, occurred in  

Options:
A) 2005-06   
B) 2006-07   
C) 2007-08   
D) 2008-09 
E) None of these
Solution:
Ans: (d) Percentage growth from 2005-06 to 2006-07 = \(\cfrac{100-50}{50}\times 100\% = 100\%\)

Percentage growth from 2006-07 to 2007-08 = \(\cfrac{200-100}{100}\times 100\% = 100\%\)

Percentage growth from 2007-08 to 2008-09 = \(\cfrac{250-200}{200}\times 100\% = 25\%\)

Percentage growth from 2008-09 to 2009-10 =\(\cfrac{400-250}{250}\times 100\% = 60\%\)

Knowledge Expert

· commented

· 1 Months ago

Do re read the question, and observe the solution.

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