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Raghavendra B K

· started a discussion

· 1 Months ago

Wrong Answer (Question: 110891.0 )

When we split y^2-y-30=0, we get y^2-6y+5y-30=0 and hence the solutions will be y= 6,-5 which finally gives y>=x. Please Clarify

Question:
DIRECTION : In the given question two equations numbered I and II are given. You have to solve both the equations and Give answer if


I. x2 + x – 20 = 0 

II. y2 – y – 30 = 0

Options:
A) x > y
B) x ≥ y
C) x < y
D) x ≤ y
E) x = y or the relationship cannot be established
Solution:

x2+ x – 20 = 0

x2 + 5x – 4x – 20 = 0

x(x + 5) -4(x + 5) = 0

x = -5, 4

II. y2 – y – 30 = 0

y2 - 6y + 5y – 30 = 0

y (y - 6) + 5(y - 6) = 0

y = 6, -5

kanhaiya jha

· commented

· 1 Months ago

From I,

x = -5, 4

From II,

y = 6, -5

Now compare,

-5<6 means x<y
4<6 means x<y
-5=-5 means x=y
4>-5 means x>y

Here all the three inequalities appears which is not possible..Thats why no relation can be established between x and y...
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