CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Tags:

Articles

Discussions
Submit Discussion
Raghavendra B K

· started a discussion

· 1 Months ago

Wrong Answer (Question: 104269.0 )

In the description it is evident that x= -2, -3 and y= -3.2, -2.5. But the answer says x=y. Please clarify.

Question:
DIRECTIONS: In each question two equations numbered I and II are given. You have to solve both the equations and Give Answer If


I. x2 + 5x + 6 = 0

II. 4y2 + 24y + 35 = 0

Options:
A) x < y
B) x > y
C) x ≥ y
D) x ≤ y
E) x = y or relationship between x and y cannot be established.
Solution:

I. x2 + 5x + 6 = 0

⇒ x2 + 3x + 2x + 6 = 0

⇒ x(x + 3) +2 (x + 3) = 0

⇒ (x + 2) (x + 3) = 0

⇒ x = - 2 or – 3

II. 4y2 + 24y + 35 = 0

⇒ 4y2 + 14y + 10y + 35 = 0

⇒ 2y(2y+ 7) +5(2y + 7) = 0

⇒ (2y+ 7) (2y + 5) = 0

⇒ y = - \(\frac{7}{2}\)  or - \(\frac{5}{2}\)  = -3.5 or  - 2.5

Amit

· commented

· 1 Months ago

when u put it n no.line we get -3.5(y) -3(x) -2.5(y) -2(x) as u can see there cannot be clear relation hence it is right x=y or no relation holds true

Prashant Indurwar

· commented

· 1 Months ago

x<y and x>y so relation cant be established.

Raghavendra B K

· commented

· 1 Months ago

Thank you

Ankesh

· commented

· 1 Months ago

option e is for both cases. x = y or relationship between x and y cannot be established. Here the relationship between x and y cannot be established. That is why the answer is e.
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions