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Prabhakar kumar

· started a discussion

· 1 Months ago

wrong answer (Question: 103286.0 )

why not answer is B
when X>= y.

Question:
Directions : In the given question two equations numbered I and II are given. You have to solve both the equations and Give answer if


I. 2x2 + 3x – 20 = 0

II. 2y2 + 19y + 44 = 0

Options:
A) X > Y
B) X ≥ Y
C) X < Y
D) X ≤ Y
E) X = Y or the relationship cannot be established
Solution:

I. 2x2 + 3x – 20 = 0

⇒ 2x2 + 8x – 5x – 20 = 0

⇒ 2x (x + 4) -5 (x + 4) = 0

⇒ (x + 4) (2x – 5) = 0

⇒ x = - 4 or \(\frac{5}{2}\)            

II. 2y2 + 19y + 44 = 0

⇒ 2y2 + 11y + 8y  + 44 =0

⇒ y(2y + 11) +4 (2y + 11) = 0

⇒ (y + 4) (2y + 11) = 0

⇒ y = -4 or - \(\frac{11}{2}\)

Knowledge Expert

· commented

· 1 Months ago

same answer has been given..please check...
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