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Rajat

· started a discussion

· 1 Months ago

WHY YOU DONE SQUARE? (Question: 110892.0 )

WHY YOU SQUARE IN Y'S EQUATION HENCE IT IS A PERFECT SQUARE OF 15

Question:
DIRECTION : In the given question two equations numbered I and II are given. You have to solve both the equations and Give answer if


I. 225x2 – 4 = 0

II. \(\sqrt{225y}\)  + 2 = 0

Options:
A) x > y
B) x ≥ y
C) x < y
D) x ≤ y
E) x = y or the relationship cannot be established
Solution:

I. 225x2 – 4 = 0

225x2 = 4

x2 = \(\frac{4}{225}\) 

x = \(\sqrt{\frac{4}{225}}\)  = ± \(\frac{2}{15}\) 

II. \(\sqrt{225y}\)  + 2 = 0

 \(\sqrt{225y}\) = -2

Squaring both sides we get, 

225y = 4

y = \(\frac{4}{225}\)  

akshata

· commented

· 1 Months ago

because y is in root
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