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nivi

· started a discussion

· 1 Months ago

tank (Question: 120275.0 )

108 180 9,6 are from where?

Question:
Two pipes A and B can fill a tank in 20 h and 30 h respectively. Both the pipes are opened to fill the tank but when the tank is 1/3 full, a leak develops in the tank. Due to this leakage one-third of the water supplied by pipes A and B goes waste. What is the total time to fill the tank if the leak is not closed?
Options:
A) 12 h
B) 16 h
C) 18 h
D) 20 h
E) None of these
Solution:

Efficiency of first pipe = 100/20 = 5% per hour.

Efficiency of second Pipe = 100/30 = 3.33% per hour.

Efficiency of both pipe together = 5 + 3.33 = 8.33% per hour.

1/3 i.e. 33.33% tank be filled by these two pipes in = 33.33/8.33 = 4 hours.

Now, tank is empty and it need to be filled from zero. So

Time taken to Fill the empty tank = 100/8.33 = 12 hours.

So, Total time taken to filled the tank = 4 + 12 = 16 hours.

Knowledge Expert

· commented

· 1 Months ago

:)

nivi

· commented

· 1 Months ago

thank you

Knowledge Expert

· commented

· 1 Months ago

I think this will be very clear to you:

Efficiency of first pipe = 100/20 = 5% per hour.

Efficiency of second Pipe = 100/30 = 3.33% per hour.

Efficiency of both pipe together = 5 + 3.33 = 8.33% per hour.

1/3 i.e. 33.33% tank be filled by these two pipes in = 33.33/8.33 = 4 hours.

Now, tank is empty and it need to be filled from zero.

So, Time taken to Fill the empty tank = 100/8.33 = 12 hours.

So, Total time taken to filled the tank = 4 + 12 = 16 hours.

nivi

· commented

· 1 Months ago

u r giving the same xplanation as being given sir
please elaborate m not getting that

Knowledge Expert

· commented

· 1 Months ago

Let us assume total work = 180 (we are not assuming it to be LCM of 20 and 30 = 60 because in that case 1/3rd of A + B will be fractional)
Time taken to fill 1/3rd of the tank = 60/(9+6) = 4 h
Due to leakage, net inflow = 2/3 * (9 + 6) = 10 units
Time taken to fill remaining 120 units = 12 h
So total time taken = 12 + 4 = 16 h
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