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vignesh

· started a discussion

· 1 Months ago

sum (Question: 157223.0 )

13*13=169
31*31=961
14*14=196

there are two odd number possible so cannot be answer the question

Question:
If it is possible to form only one such number with the 3rd, 6th and the 7th digits of the number 7394261 but not in the same order , which is the perfect square of a two digit odd number, then which of the following will be the unit digit of the two digit odd number?
Options:
A) 9
B) 3
C) 5
D) 2
E) 6
Solution:

Ans: (b) 


Knowledge Expert

· commented

· 1 Months ago

3rd 6th and 7th digits are 9, 6, 1.... perfect squares containing these digits are 13 = 169, 14 = 196 and 31 = 961.. 31 cant be the answer as it is stated in question " but not in the same order". 14 also cant be the answer as we need an odd digit so 13 is the correct answer
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