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Ankit Gupta

· started a discussion

· 1 Months ago

solve it (Question: 113731.0 )

please solved it by another method??

Question:
A certain amount of money lent at compound interest becomes 2.25 times itself in 3 years. If the rate of interests for the first, second and the third years are in the ratio 4 : 5 : 10, find the rate of interest for the third year given that the interest is compounded annually?
Options:
A) 30%
B) 45%
C) 50%
D) 55%
E) None of these
Solution:
Ans: (c)

Choosing option (A), the rate of interests will be 12%, 15% and 30%. The net interest in this case will be definitely less than 125%

Similarly choosing option (C), the rate of interests will be 20%, 25% and 50%

The net interest in this case will be 125%


Alternate solution:


Compound Interest = 1.25


Now, apply formula,


CI = a+b+c + (ab+bc+ca)/100 + abc/100^2


put a=4x, b=5x, c=10x and CI = 1.25


On simplifying,


2x^3 + 110x^2  + 1900x - 12500 = 0


By hit and trial method,


x=5


So, third year interest = 10x = 10*5 = 50%

kanhaiya jha

· commented

· 1 Months ago

@Amit Singh Sahaye

Compound Interest = 1.25

Now, apply formula,

CI = a+b+c + (ab+bc+ca)/100 + abc/100^2

put a=4x, b=5x, c=10x and CI = 1.25

On simplifying,

2x^3 + 110x^2 + 1900x - 12500 = 0

By hit and trial method,

x=5

So, third year interest = 10x = 10*5 = 50%

kanhaiya jha

· commented

· 1 Months ago

Compound Interest = 1.25

Now, apply formula,

CI = a+b+c + (ab+bc+ca)/100 + abc/100^2

put a=4x, b=5x, c=10x and CI = 1.25

On simplifying,

2x^3 + 110x^2 + 1900x - 12500 = 0

By hit and trial method,

x=5

So, third year interest = 10x = 10*5 = 50%

Amit Singh Sahaye

· commented

· 1 Months ago

solve another method
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