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ashok kumar

· started a discussion

· 1 Months ago

Solution is wrong (Question:607215.0)

That is
60*16=X*16*1.2
= 50

Question:

60 men can do a piece of work in 16 days.

Quantity I- one third of men which would be required to do the same work in 20 days?

Quantity II- If efficiency of each men increases by 20 %, then work will be completed in how many days?

Options:
A) Quantity I > Quantity II
B) Quantity I < Quantity II
C) Quantity I ≥ Quantity II
D) Quantity I ≤ Quantity II
E) Quantity I = Quantity II or the relation can’t be determined
Solution:
Ans: (A) 

Quantity I:

16*60=20*?

?=48 men

one third of 48=16 

Quantity II- 

If the efficiency of each men is increases by 20 %, then they will complete the whole work in  

16*60=(60*1.2)?

?=(40/3) days

Knowledge Expert

· commented

· 1 Months ago

We corrected it. It won't change the answer option A) Quantity I > Quantity II
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