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ATUL LOKHANDE

· started a discussion

· 1 Months ago

shortcut method (Question: 338602.0 )

plese provide shortcut method of this quastion

Question:
A vessel contains a mixture of milk and water in the respective ratio of 5 : 3. 40 liters of mixture was taken out and replaced with the same quantity of milk consequently the resultant ratio between the quantities of milk and water in the mixture became 2 : 1. If 15 liters of this mixture is again taken out from the vessel, what is the resultant quantity of water in the mixture(in liters)?
Options:
A) 100
B) 105
C) 110
D) 115
E) None of these
Solution:

Let the initial quantity of milk and water in the vessel be 5x and 3x respectively.

In 40 liters of mixture, 

milk = 5 ×40/8 = 25 liters

Water = 3 × 40/8 = 15 liters

⇒ \(\cfrac{5x-25+40}{3x-15}\) = 2/1

i.e., 5 x + 15 = 6x – 30

⇒x = 45 liters

Quantity of water = (3 × 45) – 15 = 120

Quantity of water in 15 liters of mixture = 1/3 × 15 = 5 liters

Required quantity of water = 120 – 5 = 115 liters.

Knowledge Expert

· commented

· 1 Months ago

Dear Student, Please read the text given very carefully you will get it. Keep Learning with Us Best Wishes Team Toprankers
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