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· started a discussion

· 1 Months ago

A=52.49*100/145=36.20
B=61.20*100/136=45
A+B=36.20+45=81.20 Ans

Question:
DIRECTIONS: Following line-graph shows the percentage profit earned by two companies A and B during the period of 2005 to 2011. 



If the income of Company A in 2007 and that of B in 2009 are \(\unicode{x20B9} \)52.49 lakh and \(\unicode{x20B9} \) 61.2 lakh respectively, what is the total expenditure of Company A in 2007 and that of B in 2009 ? 
Options:
A) \(\unicode{x20B9} \)79.6 lakh.
B) \(\unicode{x20B9} \)80.4 lakh. 
C) \(\unicode{x20B9} \)81.2 lakh. 
D) \(\unicode{x20B9} \)82.5 lakh. 
E) \(\unicode{x20B9} \)92.5 lakh. 
Solution:

Ans: (c) EA =52.49 X 100/145 =36.2 lakh

EB =61.2 X 100/136 =45 lakh

Total expenditure = 36.2 + 45 = 81.2 lakh

Knowledge Expert

· commented

· 1 Months ago

Dear Student, In 2006, Profit % of B = 40 In 2010 Profit % of A = 40 Total Income of Company A in 2010 and Company B in 2006 = 133 lakh You must know the formula: Profit % = [(Income-Expenditure) / Expenditure] *100 40 = [(133-x)/x]*100 40x/100 =133-x 40x/100 + x = 133 140x/100 = 133 x=(133*100)/140 x=95 lakhs Keep Learning with Us Best Wishes Team Toprankers

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