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Sam Ahuja

· started a discussion

· 1 Months ago

regarding ans . (Question:157150.3)

the question is asking "no. of digit which appear twice" not "more than twice".

Question:

DIRECTIONS: Study the arrangement carefully and answer the questions given below.


4 2 6 1 3 8 9 5 8 1 6 5 1 5 8 5 3 9 4 9 2 3 2 1 5 7 2 6 2 4 2 7 4 

If one is added to each of the even digits and two is added to each of the odd digits given in the above’ arrangement, then how many digits will appear twice in the new number thus formed?
Options:
A) None 
B) One 
C) Two 
D) Three 
E) More than three
Solution:

Ans: (e) 

When one is added to each of the even digits and two is added to each of the odd digits, then the new numbers are

5,3,7,3,5,9, 11,7,9,3,7,7, 3,7,9,7,5, 

11,5,11,5,3,3,7,3,7,3,5,3,9,5

The digits which appear twice are 

5, 3, 7, 9, 11. So, it is more than three.

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· commented

· 1 Months ago

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