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Pooja Mistry

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· 1 Months ago

r (Question:171483.0)

r

Question:
A finishes \(\cfrac{6}{7}\)th of the work in 2z hours, B works twice as fast and finishes the remaining work. For how long did B work?
Options:
A) \(\left ( \cfrac {2}{3} \right ) z\)
B) \(\left ( \cfrac {6}{7} \right ) z\)
C) \(\left ( \cfrac {6}{49} \right ) z\)
D) \(\left ( \cfrac {1}{6} \right ) z\)
E) None of these
Solution:
Ans: (d) Since A finishes \(\cfrac{6}{7}\)th of the work in 2z hours.

B would finish \(\cfrac{12}{7}\)th of the work in 2z hours.

Thus, to do \(\cfrac{1}{7}\)th of the work (which represents the remaining work), B would require \(\cfrac{2z}{1z}\) = \(\cfrac{z}{6}\) hours. Option (d) is correct. 

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