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RICKY RAJAN

· started a discussion

· 1 Months ago

question no 54 (Question: 99948.0 )

its asked about largest 4 digits no but the solution provided its given least 4 digits no so and should be 9840 instead of 9720

Question:
The largest four digit number exactly divisible by each of 12, 15, 18 and 27 is:
Options:
A) 9690
B) 9720
C) 9930
D) 9960
E) None of these
Solution:

LCM of 12, 15, 18 and 27 = 540

The least 5 digit number is 10000,

which when divided by 540 leaves 280 as the remainder.

Hence, 10000 – 280 = 9720 which will be the highest possible 4 digit number which will be completely divisible by 540.

Knowledge Expert

· commented

· 1 Months ago

yes, its known to all...but we need to find the largest four digit number exactly divisible by each of 12, 15, 18 and 27...Thats why 9720 will be the required number... Sol: LCM of 27,18,12,15 is 540. when we divide 9999 by 540 we get 279 remainder. So answer will be 9999-279 = 9720
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