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· started a discussion

· 1 Months ago

In a village, each of the 60% of families has a cow; each of the 30% of families has buffalo and each of the 15% of families has both a cow and a buffalo. In all there are 96 families in the village. How many families do not have a cow or a buffalo?

(a) 24

(b) 25

(c) 26

(d) 27

SUYASH KILLEDAR

· commented

· 1 Months ago

(96*60%)+(96*30%)-(96*15%) = family having (Cow+Buffalo)
=> 72
families do not have cow and buffalo = 96-72
= 24

so, correct answer is (a)

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