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AMIT KUMAR

· started a discussion

· 1 Months ago

please check it (Question: 89812.0 )

is it wrong ??

Question:
If all 'S' come together, then in how many ways the letters of the word SUCCESSFUL be arranged?
Options:
A) 10080
B) 40080
C) 2378 
D) 1825
E) None of these
Solution:

Ans:(a) Since all three S’s are together, hence there will be 8 letters of which C occurs 2 times and U occurs 2 times.

Thus the required number of arrangements = \(\cfrac{8!}{2!×2!}\)

= 10080

Knowledge Expert

· commented

· 1 Months ago

No its correct.....required number of ways = 8!/(2!*2!) = 10080...


Note we have 10 letters in which S appears thrice and these three S will be considered as 01 letter and remains 7 letters we have in which U appears twice, also C appears twice.....so 8! will be divided by 2!*2!...And on calculation you will get 10080....Thats it....
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