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vijay

· started a discussion

· 1 Months ago

please cheak (Question: 99775.0 )

sir 12000 answer hoga please cheak

Question:
The cost of 2 sarees and 4 shirts is \(\unicode{x20B9} \)16000 while 1 saree and 6 shirts cost the same. The cost of 12 shirts is :
Options:
A) \(\unicode{x20B9} \)12,000  
B) \(\unicode{x20B9} \)24,000
C) \(\unicode{x20B9} \)48,000
D) \(\unicode{x20B9} \)25,000
E) Can’t be determined
Solution:

Ans (b) Let cost of 1 saree = Rs. x

cost of 1 shirt = \(\unicode{x20B9} \) y

∴ 2x + 4y = 16000 …(i)

and x + 6y = 16000 …(ii)

Multiplying (ii) by 2 and subtracting (i) from it, we get,

8y= l6000⇒ y= 2000

∴ cost of 12 shirts = = (\(\unicode{x20B9} \)2000 ×12)

= \(\unicode{x20B9} \)24000

Knowledge Expert

· commented

· 1 Months ago

@TANYA CHOUDHRY you both are wrong........24000 is the correct answer...

Let cost of one saree and shirt be x and y, respectively.
2x + 4y = 16000 ....(i)
x + 6y = 16000 ....(ii)

On multiplying Eq. (ii) by 2 and subtracting from Eq. (i). we get
2x + 4y = 16000
2x + 12y = 32000
-------------------------
-8y = -16000
∴ y = 2000

Putting the value of y in Eq. (ii), we get
x +6 x 2000 = 16000
∴ x = 4000
∴ Cost of 12 shirts = 12y
= 12 x 2000 = ₹ 24000

TANYA CHOUDHRY

· commented

· 1 Months ago

12000 hi hoga
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