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Isaac Koheiding

· started a discussion

· 1 Months ago

all of the partice set for IBPS PO exam

Question:
Solve the series given below.


\(\cfrac{4}{3}, \cfrac{9}{15}, \cfrac{14}{27}, \cfrac{24}{51}\)
Options:
A) \(\cfrac{15}{39}\)
B) \(\cfrac{19}{39}\)
C) \(\cfrac{16}{37}\)
D) \(\cfrac{18}{37}\)
E) None of these
Solution:
(b) The series is : 

\(\cfrac{4+5}{3\times5}=\cfrac{9}{15}\)

\(\cfrac{9+5}{3\times9}=\cfrac{14}{27}\)

\(\cfrac{14+5}{3\times13}=\cfrac{19}{39}\)

\(\cfrac{19+5}{3\times17}=\cfrac{24}{51}\)

swetha

· commented

· 1 Months ago

Yet to be approved!

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