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Veeru K

· started a discussion

· 1 Months ago

in this question

Question:
DIRECTIONS: Answer the questions on the basis of the information given below.


The five balls in a shop A, B, C, D and E each having a different weight.

(i)   A weighs twice as much as B.

(ii)  B weighs four and a half times as much as C.

(iii) C weighs half as much as D.

(iv) D weighs half as much as E.

(v)  E weighs less than A but more than C.

E is lighter than which of the following two balls?     
Options:
A) A, B    
B) D,C
C) A,C   
D) A, D
E) B, D
Solution:
Ans (a) 

A = 2B

B = 9 C/2 = 4.5 C

C = D/2

D = E/2

∴ A = 2B = 9C = 4.5 D = 2.25 E,

So,C < D < E < B < A  

So, E is lighter than A and B.  

Knowledge Expert

· commented

· 1 Months ago

@Veeru K Whats your doubt?

Veeru K

· commented

· 1 Months ago

plz comment here!!

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