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nc chourasiya

· started a discussion

· 1 Months ago

nc (Question: 68166.0 )

it seems wrong solution as 2 hours for 20 kmph and 2 hours for 2*20kmph not considered

Question:

Chirag starts walking towards the south from his initial position at a speed of 20 km/hr. After two hours, he turns left and doubles his speed.He stops after walking for another two hours. He then turns right, walks for one more hour at the same speed and then stops. What was the distance between initial and final point?

Options:
A) \(88\sqrt{2}\)
B) \(80\sqrt{2}\)
C) \(83\sqrt{2}\)
D) \(89\sqrt{2}\)
E) \(75\sqrt{2}\)
Solution:

Ans: (b)


AD is the distance between initial and final position of Chirag.

AD = AE + ED= \(40\sqrt{2} + 40\sqrt{2} = 80\sqrt{2}\)

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
No the Question and answer as given are both correct.

Best Wishes
Team TopRankers

Knowledge Expert

· commented

· 1 Months ago

hi, 80√2 is the correct answer.......a typing error occurred....we fixed it.......
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