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bhawna

· started a discussion

· 1 Months ago

maths 54th question (Question: 99914.3 )

please give in detail how to solve square root of large digit like 888888

Question:
DIRECTIONS: What approximate value should come in place of question mark (?)? (You are not expected to calculate the exact value.)
\(\sqrt{888888}\times 1.846 = ?\)
Options:
A) 1200 
B) 1000
C) 1600 
D) 1400
E) 800
Solution:
?= \(\sqrt{888888}\times 1.846 \)

=943 × 1.8 = 1600

∴ Approximate answer = 1600

Knowledge Expert

· commented

· 1 Months ago

@bhawna yes, thats why we take nearest square root in simplification.....

888888>810000

so, its square root must be 900+........so calculate the rest data with same tricks...

bhawna

· commented

· 1 Months ago

but for that we have to learn value in log for eg log88.8888

Knowledge Expert

· commented

· 1 Months ago

Its preety easy,
you must be knowing logarithm, apply here to get it quickly:

x=Square root(888888)
Applying log(base 10) on both side
log x=(1/2)[log(88.8888*10^4)]
Here log(a*b)=loga+logb
Also log(10^4)=4
log x=(1/2)[log(88.8888)+4]
log x=(1/2)[1.9488+4}
log x=(1/2)[5.9488]
log x=2.9744
x= 10^2.9744 (base is 10)
x=942.80
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