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Monuj Konwar

· started a discussion

· 1 Months ago

l (Question: 88864.0 )

i didnt understandthe last part, why A & D?

Question:
A can complete a piece of work in 4 days. B takes double the time taken by A, C takes double that of B, and D takes double that of C to complete the same task. They are paired in groups of two each. One pair takes two-thirds the time needed by the second pair to complete the work. Which is the first pair?
Options:
A) A and B
B) A and C
C) B and C
D) A and D
E) None of these
Solution:
Ans: (d) Work done in one day by A, B, C and D are

\(\cfrac{1}{4},\cfrac{1}{8},\cfrac{1}{16}\) and \(\cfrac{1}{32}\) respectively.

By using choices, we note that the pair of B and
C does \(\cfrac{3}{16}\) of work in one day; the pair of A and D does \(\cfrac{1}{4}+\cfrac{1}{32}=\cfrac{9}{32}\) of the work in one day. Hence, A and D take \(\cfrac{32}{9}\) days.
B and C take \(\cfrac{16}{3}=\cfrac{32}{6}\) days.
Hence, the first pair must comprise of A and D.

kanhaiya jha

· commented

· 1 Months ago

Work done in one day by A, B, C and D are
1/4,1/8,1/16 and 1/32 respectively.
By using choices, we note that the pair of B and C do 3/16 of work in one day;
the pair of A and D do 1/4+1/32=9/32 of the work in one day.
Hence, A and D take 32/9 days.
B and C take 16/3=32/6 days.
Hence, the first pair must comprise of A and D.
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