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kumarnitin

· started a discussion

· 1 Months ago

jitendra (Question: 89850.0 )

i could not get this please how you found younger son age 14x?

Question:
A father’s age is four times the age of his elder son and five times that of his younger son. When the elder son has lived to three times his present age, then the father’s age will exceed twice that of his younger son by three years. What is the father’s age?
Options:
A) 30
B) 32
C) 40
D) Data insufficient.
E) None of these.
Solution:

Let the age younger son is 4x years

the age of elder son is 5x years

∴ Father's age= 20x years

when the elder son's age will be thrice, i.e. 5x×3 years

(15x=5x+10x)

age of Younger son=4x+10x=14x  years

Father's age= 20x+10x=30x  years

From the question, 30x=2×14x+3

30x=28x+3

2x=3

⟹x=1.5  years

∴ Father's present age =20x years

=20 ×1.5 =30 years

Knowledge Expert

· commented

· 1 Months ago

@kumarnitin

its obvious when the elder son's age will be thrice, i.e. 5x×3 years, (15x=5x+10x)

elder son's age increased by 10x, therefore younger son's age also will increase by 10x.

kumarnitin

· commented

· 1 Months ago

explain please
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